JHS3 Mathematics · Term 2, Week 8

Variables and Equations

Lesson notes

Learning Objectives

Indicator: B9.2.3.1.1 - Solve single variable linear inequalities with rational coefficients.

By the end of the lesson, learners can:

  1. Solve single variable linear inequalities with rational coefficients (fractions and decimals), using addition, subtraction, multiplication and division properties.
  2. Apply the rule of reversing the inequality sign when multiplying or dividing both sides by a negative number.
  3. Verify solutions to inequalities by substituting values back into the original inequality.
  4. Write solution sets in set-builder notation and describe them in words.

This lesson focuses on the solving process only. Graphing solution sets on the number line is scheduled for Term 2, Week 9, so that work will not be introduced today.

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Curriculum details

Strand
Algebra (Strand 2)
Sub-strand
Variables and Equations (2.3)
Content standard
B9.2.3.1 - Demonstrate understanding of single variable linear inequalities with rational coefficients including: • solving inequalities • verifying • comparing • graphing
Indicator
B9.2.3.1.1 - Solve single variable linear inequalities with rational coefficients.
Suggested placement
Term 2, Week 8 (Week 20 of the year)

Our suggestion, laid out in curriculum order across three terms of twelve weeks. NaCCA does not fix the week, so follow your school's scheme of learning.

Curriculum reference
Mathematics, Common Core Programme (JHS1-JHS3), 2023, p. 190

Transcribed from the official NaCCA publication. Check this page against the source.

Exemplars (from the NaCCA curriculum)

Wide black-and-white mathematical teaching visual is organised as a worked calculation with vertical divisions, open...
A wide black-and-white mathematical teaching visual is organised as a worked calculation with vertical divisions, open white space around the main marks. Visible labels, values, and notation include: i.; ii.; iii.; iv.; 2x+7>}; 1-÷*>}; 3y-3<5; 17 +x> (7 - xg)}; V.; vi.; vii.; viii.; }>x; 1(2x+3)≤x+1; 2-<3+x; 5x+3≥0.
i. 2x + 7 > 5 v. 1 > x - 4
2 3 5
ii. 4 - 1 x > 2 vi. 1 (2x + 3) ≤ x + 1
5 5 7 2
iii. 3 y - 2 < 4 vii. x + 1 ≥ - 3
2 5 5 2 2
iv. 1 (5x - 4) < x + 11 viii. - 2 x + 3 ≥ 0
2 24 3