SHS2 Mathematics · Semester 2, Week 15

Statistical Reasoning and Its Application in Real Life

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Notes for this lesson are being prepared. The curriculum details below are complete and ready to use for your planning.

Curriculum details

Strand
Making Sense of and Using Data (Strand 4)
Sub-strand
Statistical Reasoning and Its Application in Real Life (4.1)
Content standard
2.4.1.CS.2 - Demonstrate an understanding of data presentations and analysis for grouped and ungrouped data and describe the relationship between the measures of dispersion in data displays. 2.4.1.LO.2 Construct and interpret a variety of data presentation methods, including cumulative frequency curves (Ogive), waffle diagrams, etc. and describe the relationship between the measures of dispersion in data displays to solve and/or pose problems.
Indicator
2.4.1.LI.2 - Analyse and interpret data using measures of dispersion and justify which of these measures best suits the data.
Suggested placement
Semester 2, Week 15 (Week 35 of the year)

Our suggestion, laid out in curriculum order across three terms of twelve weeks. NaCCA does not fix the week, so follow your school's scheme of learning.

Source document note

The official curriculum document has a fault in this entry, so the curriculum text above is transcribed exactly as printed:

  • exemplars - p.281: the equation text on this page is set in a CambriaMath subset whose /ToUnicode map doubles every letter and gets many of them wrong, and the glyph ids could not be lined up with the extraction to repair it, so any italic variable here may be doubled or be the wrong letter; read the page
  • exemplars - p.285: this exemplar sets a two-dimensional construct - a stacked fraction, an index or a column vector - which the text layer flattens into separate lines, so the parts are present but their vertical arrangement is lost; read the page
Curriculum reference
NaCCA curriculum document, p. 281

Exemplars (from the NaCCA curriculum)

Using Talk for Learning strategies, learners brainstorm on the meaning of standard deviation.
Example: Standard deviation tells about the value and how much it has deviated from the mean value. If we get a low standard deviation, then it means that the values tend to be close to the mean, whereas a high standard deviation tells us that the values are far from the mean value. It is commonly abbreviated as SD and denoted by 'σ'.
Using think-pair-share activities, learners discuss the steps in determining standard deviation and deduce the formula for Standard deviation.
Steps to Calculate Standard Deviation
- Find the mean, which is the arithmetic mean of the observations.
- Find the squared differences from the mean. (The data value - mean) 2
- Find the average of the squared differences. (Variance = The sum of squared differences ÷ the number of observations).
- Find the square root of variance. (Standard deviation = √Variance).
Standard Deviation Formulae: Two standard deviation formulas are used to find the standard deviation of sample data and the standard deviation of the given population. 
Figure from the shs2 mathematics curriculum, printed page 282
Standard Deviation of Ungrouped Data: The calculations for standard deviation differ for different data. Distribution measures the deviation of data from its mean or average position. There are two methods to find the standard deviation.
Standard Deviation by the Actual Mean Method σ = √(∑x−¯x)2/n)
Example: Consider the data observations 3, 2, 5, 6. Here, the mean of these data points is 16/4 = 4. The squared differences from mean = (4-3) 2 +(2-4) 2 +(5-4) 2 +(6-4) 2 = 10 Variance = Squared differences from mean/ number of data points =10/4 =2.5 Standard deviation = √2.5 = 1.58.
Standard deviation by Assumed Mean Method: When the x values are large, an arbitrary value (A) is chosen as the mean. The deviation from this assumed mean is calculated as d = x - A.
σ = √[(∑(d) 2 /n) - (∑d/n) 2 ]
Using Talk for Learning: Learners brainstorm on the meaning of variance.
Example: Variance is a measure of dispersion. A measure of dispersion is a quantity that is used to check the variability of data about an average value. Data can be of two types - grouped and ungrouped. When data is expressed in the form of class intervals, it is known as grouped data. On the other hand, if data consists of individual data points, it is called ungrouped data. The sample and population variance can be determined for both kinds of data.
Using think-pair-share activities, learners discuss the steps in determining variance and deduce the formula for variance. Learners should be encouraged to use feasible technology to analyse data, determine the variance of the data, and talk about the appropriate ways of using the IT tools.
Example
- Find the mean of the observations.
- Subtract the mean from each observation.
- Square each of these values.
- Add all the values obtained in the previous step.
- Divide the value from step 4 by n (for population variance) or n - 1 (for sample variance). 
Figure from the shs2 mathematics curriculum, printed page 283
Examples: i. Suppose we have the data set {3, 5, 8, 1}, and we want to find the population variance. The mean is given as (3 + 5 + 8 + 1) / 4 = 4.25. Then by using the definition of variance we get [(3 - 4.25) 2 + (5 - 4.25) 2 + (8 - 4.25) 2 + (1 - 4.25) 2 ] / 4 = 6.68. Thus, variance = 6.68.
ii. Find the sample variance of the data (3, 4, 7, 12, 14).
Solution: n = 5 Mean = (3 + 4 + 7 + 12 + 14) / 5 = 8 Sample Variance = ∑(Xi−𝑋̅ ) 2 /N−1 [(3 - 8) 2 + (4 - 8) 2 + (7 - 8) 2 + (12 - 8) 2 + (14 - 8) 2 ) / 5 - 1 = 23.5
Answer: Variance = 23.5
iii. Find the population variance of the data (1.2, 4.5, 6.7, 2.3).
Solution: n = 4 Mean = (1.2 + 4.5 + 6.7 + 2.3) / 4 = 3.675 Population Variance = ∑(Xi−X) 2 /N [(1.2 - 3.675) 2 + (4.5 - 3.675) 2 + (6.7 - 3.675) 2 + (2.3 - 3.675) 2 ] / 4 = 4.461
Answer: Variance = 4.461
iv. Find the sample variance of Class 10 - 20 - 30 - 40 - 50 - 20 30 40 50 60
Frequency 2 5 7 3 1
Solution: The height of the interval is 10 Class F Mi d = (Mi - fd d 2 f B) / 10 10 - 20 2 15 -2 -4 8 20 - 30 5 25 -1 -5 5 30 - 40 7 35 = 0 0 0 B 40 - 50 3 45 1 3 3 50 - 60 1 55 2 2 4
∑𝑀𝑀𝑀𝑀𝑀𝑀𝑀𝑀 Mean = = 32.778. ∑𝑓𝑓𝑓𝑓
(∑𝑓𝑓𝑓𝑓) ∑𝑓𝑓𝑑𝑑 2 − Variance = 2𝑛𝑛 .10 2 = 112.4183. [This formula can be derived from ∑f(Mi−¯¯¯¯¯X)2N−1 to 𝑛𝑛−1 simplify calculations] Answer: Variance = 112.4183.
Using Talk for Learning: Learners brainstorm on the meaning of Quartile Deviation.
Example: Quartile deviation is a statistic that measures the deviation in the middle of the data. Quartile deviation is also referred to as the semi-interquartile range and is half of the difference between the third quartile and the first quartile value. The formula for the quartile deviation of the data is 
Figure from the shs2 mathematics curriculum, printed page 285
Examples: Find the quartile deviation for the following given data. 23, 8, 5, 16, 33, 7, 24, 5, 30, 33, 37, 30, 9, 11, 26, 32
Solution: The given data points are 23, 8, 5, 16, 33, 7, 24, 5, 30, 33, 37, 30, 9, 11, 26, 32 Let us arrange this data in the following ascending order. 5, 5, 7, 8, 9, 11, 16, 23, 24, 26, 30, 30, 32, 33, 33, 37
From the above data we have Q 1 = ( 8 + 9)/2 = 17/2 = 8.5, and Q 3 = (30 + 32)/2 = 62/2 = 31
Quartile Deviation = 𝑄3−𝑄1 31−8.5 22.5 = 2 = 2 =11.25. 2
Teaching and Learning Resources:
- * Mathematical sets. * Technology tools such as computers, mobile phones, etc. * Computer software applications like GeoGebra * Graph sheets
- computer with data organising software like MS Excel,
- MS PowerPoint, etc.,
- manila cards
- flip charts
- markers
- * colour pens, etc. * Reports from analysed data * Worksheets * Posters * teaching presentations
- enquiry project-template
- A4, A3 papers
Assessment (2.4.1.AS.2). The document marks these depth-of-knowledge levels for this indicator: Level 1 Recall; Level 2 Skills of conceptual understanding; Level 3 Strategic reasoning.